COMEDK2017ChemistryRedox Reactions
When sulphur dioxide is passed in an acidified K ₂ Cr ₂ O ₇ solution, the oxidation state of sulphur is changed from
Options
- A0 +4 to 0
- B+4 to +2
- C+4 to +6
- D+6 to +4
Correct answer
C. +4 to +6
Step-by-step solution
3 SO ₂+ K ₂ Cr ₂ O ₇+ H ₂ SO ₄ K ₂ SO ₄+ Cr ₂ ( SO ₄ )₃+ H ₂ O O.N. of S in SO ₂ is aligned x+2(-2) &=0 x &=+4 aligned O.N. of S in K ₂ SO ₄ is aligned 2(1)+x+2(-4) &=0 x &=+6 aligned O.N. changes from +4 to +6 .