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COMEDK2023ChemistrySolid State

In a normal spinel type structure, the oxide ions are arranged in ccp, whereas 1 / 8 tetrahedral holes are occupied by Zn ²⁺ ions and 50 % of octahedral holes are occupied by Fe ³⁺ ions. The formula of compound is

Options

  1. AZnFe ₂ O ₄
  2. BZnFe ₂ O ₃
  3. CZnFe ₂ O ₂
  4. DZn ₂ Fe ₂ O ₄

Correct answer

A. ZnFe ₂ O ₄

Step-by-step solution

In one unit cell, number of O ²⁻=4 The number of Zn ²⁺= 1 8 8=1 The number of Fe ³⁺= 1 2 4=2 Molecular formula of given spinel structure is ZnFe ₂ O ₄

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