How many molecules of C O₂ (g) are obtained on reaction of 24 grams of methane with 4moles of oxygen?

Step-by-step solution

The balanced chemical equation for the combustion of methane is: CH₄(g) + 2O₂(g) CO₂(g) + 2H₂O(l) Molar mass of CH₄ = 16 g/mol Moles of CH₄ = 24 16 = 1.5 moles Moles of O₂ given = 4 moles From the stoichiometry, 1 mole of CH₄ requires 2 moles of O₂ . Thus, 1.5 moles of CH₄ require 3 moles of O₂ . Since 4 moles of O₂ are available, CH₄ is the limiting reagent. Moles of CO₂ produced = Moles of CH₄ reacted = 1.5 moles Number of molecules of CO₂ = 1.5 N_A = 1.5 6.022 10²³ = 9.033 10²³ Answer: 9.033 10²³