500 mL of an aqueous solution of glucose C₆ H₁₂ O₆ (Molar mass 180 gmol ⁻¹ ) contains 6.02 10²² molecules. The concentration of the solution will be:

Step-by-step solution

Number of moles of glucose is given by the ratio of the number of molecules to Avogadro's number. n = 6.02 10²² 6.02 10²³ = 0.1 mol Volume of the solution is V = 500 mL = 0.5 L. Molarity is the number of moles of solute per liter of solution. M = n V = 0.1 0.5 = 0.2 M Answer: 0.2 M