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COMEDK2024ChemistryThermodynamics (C)

One mole of an ideal gas for which C_V= 3 2 R is heated reversibly at constant pressure of 1 atm from 25^ C to 100^ C . H will be

Options

  1. A372.56 cal
  2. B3.72 cal
  3. C37256 cal
  4. D37.2 cal

Correct answer

A. 372.56 cal

Step-by-step solution

We know that, aligned & C_P=C_V+R & C_P= 3 2 R+R= 5 2 R aligned At constant pressure, heat absorb by one mole of gas (q_p ) aligned & =n C_p T=1 5 2 [100-25] R & =1 5 2 1.987 75 q_p & =372.56 cal aligned

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