0.06 mole of KNO ₃ solid is added to 100 ~cm ³ of water at 298 ~K . The enthalpy of KNO ₃(a q) solution is 35.8 ~kJ ~mol ⁻¹ . After the solute is dissolved the temperature of the solution will be

Step-by-step solution

0.06 ~mole KNO ₃ added to 100 ~cm ³ of water at 298 ~K H=35.8 ~kJ / mol H=m C T [ array l H for 0.06 mole =35.8 0.06=2.148 ~kJ Mass =100 ~cm ³=100 ~g array ] 2.148=100 0.004184 ~kJ T T=5.133 ~K It is an endothermic process as heat absorbed. So, temperature will decrease. Final temperature aligned &T=298-5.133 &T=292867 ~K 293 ~K aligned