At a particular locus, frequency of allele ' A ' is 0.6 and that of allele ' a ' is 0.4 . What would be the frequency of heterozygotes in a random mating population at equilibrium?

Step-by-step solution

In a stable population, for a gene with two alleles, ' A ' (dominant) and 'a' (recessive), if the frequency of ' A ' is p and the frequency of ' a ' is q , then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the Hardy-Weinberg equation: p^2+2 p q+q^2=1 where p^2= Frequency of AA (homozygous dominant) individuals q^2= Frequency of aa (homozygous recessive) individuals 2 p q= Frequency of Aa (heterozygous) individuals. So, p=0.6 and q=0.4 (given) aligned 2 p q( frequency of hetero