COMEDK20269 May 2026Evening ShiftPhysicsAlternating CurrentActual
When a current of 2.5 A passes through the primary coil of a transformer of 200 number turns, the magnetic flux linked with the secondary coil having 400 turns is 600 10⁻⁶ T m^2 . Find the induced emf in the secondary coil, when the current in the primary coil increases at a rate of 0.2 As⁻¹
Options
- A1.92 10⁻⁴ V
- B0.92 10⁻⁴ V
- C0.92 10⁻² V
- D1.92 10⁻² V
Correct answer
D. 1.92 10⁻² V
Step-by-step solution
The total magnetic flux linked with the secondary coil is proportional to the current in the primary coil, given by the relation: N_s _s = M I_p where M is the mutual inductance. Substituting the given values: M = N_s _s I_p = 400 600 10⁻⁶ 2.5 = 0.24 2.5 = 0.096 H The magnitude of the induced emf in the secondary coil is given by Faraday's law of induction: e_s = M dI_p dt Given the rate of change of current dI_p dt = 0.2 A s ⁻¹ , we get: e_s = 0.096 0.2 = 0.0192 V = 1.92 10⁻² V Answer: 1.92 10⁻² V