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COMEDK20269 May 2026Morning ShiftPhysicsAlternating CurrentActual

A solenoid having resistance R = 60 and inductance L = 0.4 H is connected to an AC source V = 100 2 200t . Find the maximum current.

Options

  1. A1.414 A
  2. B2.828 A
  3. C0.707 A
  4. D1.732 A

Correct answer

A. 1.414 A

Step-by-step solution

Given the AC source equation V = 100 2 (200t) , the peak voltage is V_m = 100 2 V and the angular frequency is = 200 rad/s . The inductive reactance of the solenoid is: X_L = L = 200 0.4 = 80 The impedance of the circuit is: Z = R^2 + X_L^2 = 60^2 + 80^2 = 3600 + 6400 = 100 The maximum (peak) current in the circuit is: I_m = V_m Z = 100 2 100 = 2 A Since 2 1.414 , the maximum current is 1.414 A . Answer: 1.414 A

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