What is the frequency of the electron in the first orbit of hydrogen atom of orbital radius 0.5 10⁻¹⁰ m, if its orbital velocity in that orbit is 2.2 10^6 ms⁻¹ .

Step-by-step solution

The frequency of the electron in its circular orbit is given by the formula: = v 2 r Substituting the given values v = 2.2 10^6 ms ⁻¹ and r = 0.5 10⁻¹⁰ m : = 2.2 10^6 2 0.5 10⁻¹⁰ = 2.2 10^6 10⁻¹⁰ = 2.2 10¹⁶ Using 3.14 : 2.2 3.14 10¹⁶ 0.70 10¹⁶ Hz 7.0 10¹⁵ Hz Answer : 7.0 10¹⁵ Hz.