KCET2026PhysicsAtomic Physics
The radius of first orbit in hydrogen atom is 5.3 10⁻¹¹ m. The kinetic energy E_K , potential energy E_P and total energy E_T of electron in first orbit are
Options
- AE_K = -13.6 eV , E_P = 27.2 eV , E_T = 13.6 eV
- BE_K = 13.6 eV , E_P = -27.2 eV , E_T = -13.6 eV
- CE_K = -27.2 eV , E_P = -13.6 eV , E_T = 13.6 eV
- DE_K = 13.6 eV , E_P = -6.8 eV , E_T = -13.6 eV
Correct answer
B. E_K = 13.6 eV , E_P = -27.2 eV , E_T = -13.6 eV
Step-by-step solution
The total energy of an electron in the first orbit of a hydrogen atom is known to be E_T = -13.6 eV . The relationship between kinetic energy E_K , potential energy E_P , and total energy E_T for an electron in a hydrogen atom is given by: E_K = -E_T E_P = 2E_T Substituting the value of E_T into these relations: E_K = -(-13.6 eV ) = 13.6 eV E_P = 2(-13.6 eV ) = -27.2 eV Thus, the energies are E_K = 13.6 eV , E_P = -27.2 eV , and E_T = -13.6 eV . Answer: E_K = 13.6 eV , E_P = -27.2 eV , E_T = -13.6 eV