COMEDK20269 May 2026Evening ShiftPhysicsCurrent ElectricityActual
A series combination of 'n' cells of emf 'E' and internal resistance 'r' each, are connected across the external resistance 'R'. If the internal resistance 'r' is negligibly small, then the current 'I' through the external resistance is:
Options
- AI = E R
- BI = rE n
- CI = nE R
- DI = E nR
Correct answer
C. I = nE R
Step-by-step solution
The equivalent electromotive force of n cells connected in series is nE . The equivalent internal resistance of the series combination is nr . The total resistance of the circuit is the sum of the external resistance and the equivalent internal resistance, which is R + nr . By Ohm's law, the current I flowing through the circuit is given by the ratio of total electromotive force to total resistance: I = nE R + nr It is given that the internal resistance r is negligibly small, so the term nr can be neglected in comp