A galvanometer of resistance 50 is having 30 divisions and a current sensitivity 10 mA/div. What should be the shunt resistance so that it can be converted into an ammeter of range 10A?

Step-by-step solution

The full scale deflection current of the galvanometer is given by: I_g = Number of divisions Current sensitivity I_g = 30 10 10⁻³ A = 0.3 A The shunt resistance S required to convert the galvanometer into an ammeter of range I is: S = I_g G I - I_g Substituting the given values G = 50 and I = 10 A : S = 0.3 50 10 - 0.3 S = 15 9.7 S 1.55 Answer: 1.55