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COMEDK202510 May 2025Evening ShiftPhysicsDual Nature of MatterActual

De Broglie wavelength associated with an electron accelerated through a potential difference ' V ' is ' '. If the accelerating potential is halved, what will be the new wavelength associated with the charged particle?

Options

  1. A2
  2. B2
  3. C2
  4. D2

Correct answer

B. 2

Step-by-step solution

The de Broglie wavelength of an electron accelerated through a potential difference V is given by the formula = h 2meV , where h is Planck's constant, m is the mass of the electron, and e is the charge of the electron. From this expression, it is evident that 1 V . Let the initial wavelength be ₁ = at potential V₁ = V . Let the new wavelength be ₂ at potential V₂ = V 2 . Taking the ratio of the two wavelengths: ₂ ₁ = V₁ V₂ = V V/2 = 2 . Therefore, ₂ = 2 ₁ = 2 . Answer: 2

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