When a certain metal surface is illuminated with light of frequency , the stopping potential for photoelectric current is V₀ . When the same surface is illuminated by light of frequency 2 , the stopping potential is V₀ 4 . The threshold frequency for photoelectric emission is

Step-by-step solution

According to Einstein's photoelectric equation, the maximum kinetic energy K_ max is given by K_ max = h - , where = h ₀ is the work function and ₀ is the threshold frequency. The stopping potential V₀ is related to the maximum kinetic energy by eV₀ = K_ max . Thus, eV₀ = h - h ₀ . For the first case, eV₀ = h - h ₀ . (Equation 1) For the second case, with frequency 2 and stopping potential V₀ 4 , we have e ( V₀ 4 ) = h ( 2 ) - h ₀ . (Equation 2) Multiplying Equation 2 by 4, we get eV₀ = 2h - 4h ₀ . (Equation 3) Equ