A proton accelerated through a potential V has de-Broglie wavelength . Then, the de-Broglie wavelength of an -particle, when accelerated through the same potential V is

Step-by-step solution

When a charged particle of charge q is accelerated through a potential V , then de-Broglie wavelength is given as = h 2 m q V 1 m q _ _ p = m_ p m_ q_ p q_ _ = m_ p 4 m_ p q_ p 2 q_ p [ array c m_ =4 m_ p and q_ =2 q_ p array ] _ = 1 8 _ = 2 2