COMEDK2016PhysicsDual Nature of Matter
A proton and an alpha particle are subjected to same potential difference V . Their de-Broglie wavelengths _ p , _ will be in the ratio
Options
- A2: 1
- B2 2 : 1
- C1: 1
- D1: 2
Correct answer
B. 2 2 : 1
Step-by-step solution
T he de-Broglie wavelength of a particle is given by = h m v = h p The momentum of proton, p_ p = 2 m E = 2 m e V Similarly, for - particle, aligned p_ &- 2 4 m 2 e V &= 16 m e V _ p _ &= p_ p_ p = 16 m e V 2 m e V = 8 &=2 2 : 1 aligned