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COMEDK2016PhysicsDual Nature of Matter

Work function of a photosensitive metal is 3 eV . The wavelength of incident radiations which can just eject photoelectrons from the metal is

Options

  1. A600 ~nm
  2. B510 ~nm
  3. C414 ~nm
  4. D378 ~nm

Correct answer

C. 414 ~nm

Step-by-step solution

Given, work function, =3 eV The wavelength of incident radiation is given by = h c = 1242 = 1242 3 =414 ~nm

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