A square loop of wire 2.2 cm on each side contains 2 turns and has a total resistance of 0.0002 . It is located 22 cm from a long straight current carrying wire. If the current in the straight wire is increased at a steady rate from 20 A to 50 A in 5 s, determine the magnitude of the current induced in the squared loop.

Step-by-step solution

Given: Side of the square loop, a = 2.2 cm = 0.022 m Number of turns, N = 2 Total resistance, R = 0.0002 Distance from the straight wire, d = 22 cm = 0.22 m Rate of change of current, dI dt = 50 - 20 5 = 6 A/s Since the size of the loop is small compared to its distance from the wire ( a d ), we can assume the magnetic field is approximately uniform over the area of the loop and equal to the field at its center. The magnetic field at distance d is: B = ₀ I 2 d The total magnetic flux linked with the N turns of the