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KCET2026PhysicsElectromagnetic Induction

In the figure shown, the conductor PQ of length l is moved from x = 0 to x = b and then up to x = 2b with a constant velocity v . A uniform magnetic field B is perpendicular to the plane of the paper and extends from x = 0 to x = b and it is zero from x > b . The magnitude of emf Induced in the conductor is

Options

  1. AB l x; 0 x b
  2. BZero; 0 x b
  3. CB l v; 0 x b
  4. DB l v; b x 2b

Correct answer

C. B l v; 0 x b

Step-by-step solution

When the conductor PQ moves from x = 0 to x = b , it moves through a uniform magnetic field B which is perpendicular to both its length l and velocity v . The motional emf induced across the ends of the conductor is given by the formula: E = B l v Since B , l , and v are constant, the induced emf is constant and equal to B l v in the region 0 x b . When the conductor moves from x = b to x = 2b , the magnetic field is zero ( B = 0 ). Therefore, the induced emf in this region is zero. Thus, the magnitude of emf induc

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