Uniform electric field of 5 10^3 ,NC⁻¹ is maintained in the positive Y direction. Now a point charge of 2 10⁻⁴C at rest is released from the origin. The kinetic energy attained by the charge when it is 5 m from the origin is:

Step-by-step solution

The force experienced by the point charge in the uniform electric field is given by F = qE . Since the charge is released from rest, it moves along the direction of the electric field (positive Y direction). The work done by the electric field when the charge moves a distance d is W = Fd = qEd . By the work-energy theorem, the kinetic energy attained by the charge is equal to the work done on it by the electric field. K = qEd Substituting the given values: K = (2 10⁻⁴) (5 10^3) 5 K = 10 10⁻¹ 5 K = 1 5 = 5 J. Answer