An electric field and magnetic field 1.8 10^4 Vm⁻¹ and 6 10⁻³ T respectively are applied simultaneously on an electron beam such that path of the beam remains undeviated, then the speed of the electron will be:

Step-by-step solution

For an electron beam to remain undeviated in the presence of crossed electric and magnetic fields, the net force on the electrons must be zero. F_e = F_m qE = qvB v = E B Substituting the given values: v = 1.8 10^4 6 10⁻³ v = 0.3 10^7 v = 3 10^6 ms⁻¹ Answer: 3 10^6 ms⁻¹