COMEDK2024PhysicsLaws of Motion
A block slides on rough horizontal surface with a velocity of 20 ~m / s . It comes to rest after travelling a distance of 80 m . The coefficient of kinetic friction between block and surface is (Take, .g=10 ~m / s ^2 )
Options
- A0.20
- B0.25
- C0.125
- D0.05
Correct answer
B. 0.25
Step-by-step solution
Friction force, F= N and acceleration, a= -F m =- m g m a=- g=-10 Using third equation of motion, array ll & v^2=u^2+2 a s or & 0^2=(20)^2+2(-10 ) 80 or & = (20)^2 2 10 80 = 1 4 or & =0.25 array