The motion of a particle of mass m is described by y=u t+g t² . The force acting on the particle will be

Step-by-step solution

The displacement of the particle is given by y = ut + gt^2 . The velocity v is the first derivative of displacement with respect to time t : v = dy dt = d dt (ut + gt^2) = u + 2gt . The acceleration a is the derivative of velocity with respect to time t : a = dv dt = d dt (u + 2gt) = 2g . The force F acting on the particle is given by Newton's second law, F = ma : F = m(2g) = 2mg . Answer: 2 mg