A mass of 10 ~kg is suspended from a spring balance. It is pulled a side by a horizontal string, so that it makes an angle of 60^ with the vertical. The new reading of the balance is

Step-by-step solution

Given, mass suspended from spring balance, m=10 ~kg =60^ The given situation is shown below From the diagram, reading of spring balance, F_ s =T Since, T =m g T= m g From Eqs, (i) and (ii) we get aligned F_ s &= m g = m g 60^ &=2 m g &=2 10 g &=20 ~kg - wt aligned