A monkey of mass 40 ~kg climbs up a rope which can stand a maximum tension of 600 ~N . The rope will break, when the monkey

Step-by-step solution

Mass of the monkey, m=40 ~kg Maximum tension that the rope can bear, T_ =600 ~N In option (a), acceleration of monkey, a=6 ~m / s ² (upward) By equation of motion, array ll T & -m g=m a T & =m(g+a) & =40(10+6)=640 ~N array Since, T>T_ max , hence in this case, rope will break. Therefore, option (a) is correct. In option (b), acceleration of monkey, a=4 ~m / s ² (downward) By equation of motion, T=m(g-a)=40(10-4)=240 ~N Since, T < T_ , then the rope will not break. In option (c), monkey climbs up with uniform speed,