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When a nitrogen-14 nucleus is bombarded by a deuteron, the products formed are:

Options

  1. ANitrogen-15 nucleus and an alpha particle
  2. BNitrogen-15 nucleus and a beta particle
  3. CCarbon-12 nucleus and an alpha particle
  4. DCarbon- 12 nucleus and a beta particle

Correct answer

C. Carbon-12 nucleus and an alpha particle

Step-by-step solution

The nuclear reaction: ¹⁴₇N + ^2₁H ^A_ZX + ^4₂He Conservation of mass number: 14 + 2 = A + 4 A = 12 Conservation of atomic number: 7 + 1 = Z + 2 Z = 6 Z = 6 corresponds to Carbon, A = 12 gives Carbon-12. ¹⁴₇N + ^2₁H ¹²₆C + ^4₂He The products are Carbon-12 nucleus and an alpha particle.

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