When ¹⁰ ~B ₅ nuclei are bombarded by neutrons, one of the resultant nuclei is ^7 Li ₃ . Then the emitted particle will be:

Step-by-step solution

The nuclear reaction can be represented as follows: ¹⁰₅ B + ¹₀ n ⁷₃ Li + ^ A _ Z X Applying the law of conservation of mass number (A): 10 + 1 = 7 + A 11 = 7 + A A = 4 Applying the law of conservation of atomic number (Z): 5 + 0 = 3 + Z 5 = 3 + Z Z = 2 The particle with mass number 4 and atomic number 2 is the alpha particle ( ⁴₂ He or ). Answer: Alpha particle