The binding energy per nucleon for C ¹² is 7.68 ~MeV and that for C ¹³ is 7.47 ~MeV . The energy required to remove a neutron from C ¹³ is

Step-by-step solution

The binding energy of a nucleus is given by BE = A (BE/A) , where A is the mass number and BE/A is the binding energy per nucleon. For C ¹² , BE₁₂ = 12 7.68 MeV = 92.16 MeV . For C ¹³ , BE₁₃ = 13 7.47 MeV = 97.11 MeV . The energy required to remove a neutron from C ¹³ is the difference in binding energies: E = BE₁₃ - BE₁₂ = 97.11 MeV - 92.16 MeV = 4.95 MeV . Converting this energy to Joules using 1 MeV = 1.6 10⁻¹³ J : E = 4.95 1.6 10⁻¹³ J = 7.92 10⁻¹³ J . Answer: 7.92 10⁻¹³ ~J