An object of height h is placed midway between f and 2 f in front of a biconvex lens. A real inverted image is captured on a screen placed a little beyond 2 f on the other side of the lens. If the whole arrangement is immersed in water without disturbing the object, lens and the screen positions, then the new image formed will be

Step-by-step solution

The focal length of a lens in a medium of refractive index n_m is given by the lens maker formula: 1 f_m = ( n_l n_m - 1)( 1 R₁ - 1 R₂ ) . Initially, in air ( n_m = 1 ), the focal length is f . When immersed in water ( n_m = 1.33 ), the refractive index ratio n_l n_m decreases, which increases the focal length f_m of the lens. Let the new focal length be f' > f . The object is placed at a distance u such that f f . The object position u now satisfies u When an object is placed within the focal length of a convex le