A ray of light travelling through a medium of refractive index 5 4 is incident on a glass of refractive index 3 2 . Find the angle of refraction in the glass, if the angle of incidence at the given medium - glass interface is 30^ .

Step-by-step solution

Given the refractive index of the first medium n₁ = 5 4 and the refractive index of the second medium (glass) n₂ = 3 2 . The angle of incidence i = 30^ . Using Snell's Law, n₁ (i) = n₂ (r) , where r is the angle of refraction. Substituting the given values: 5 4 (30^ ) = 3 2 (r) Since (30^ ) = 1 2 , we have: 5 4 1 2 = 3 2 (r) 5 8 = 3 2 (r) (r) = 5 8 2 3 = 10 24 = 5 12 Therefore, r = ⁻¹ ( 5 12 ) . Answer: ⁻¹ ( 5 12 )