COMEDK2016PhysicsRay Optics
Critical angle of the medium is 45^ . Polarising angle of incidence at the surface of the medium is
Options
- A45^
- B38^
- C22.5^
- D54.7^
Correct answer
D. 54.7^
Step-by-step solution
According to Brewster's law, = i_ p At critical angle, = 1 i_ C = 1 45^ array ll & = 2 & 2 = i_ p & i_ p = ⁻¹ 2 =54.7^ array