A ray of light falls upon a 60^ prism ( = 2 ) and it suffers minimum deviation. The angle of incidence for this ray must be

Step-by-step solution

Given, angle of prism, A=60^ = 2 We know that, = ( A+ _ m 2 ) A / 2 2 = ( 60^ + _ m 2 ) 60 2 ( 60^ + _ m 2 )= 2 30^ ( 60^ + _ m 2 )= 1 2 ( 60^ + _ m 2 )= 45^ 60^ + _ m 2 =45^ _ m =30^ In the case of minimum deviation, angle of incidence, i= A+ _ m 2 = 60^ +30^ 2 =45^