Applying a constant torque the speed of a flywheel is increased from 1800 rpm to 2400 rpm in 10 seconds. The number of revolutions made by the flywheel during this time is:

Step-by-step solution

Initial angular velocity ₀ = 1800 rpm = 1800 2 60 rad/s = 60 rad/s . Final angular velocity = 2400 rpm = 2400 2 60 rad/s = 80 rad/s . Time interval t = 10 s . Assuming constant angular acceleration , the average angular velocity is _ avg = ₀ + 2 = 60 + 80 2 = 70 rad/s . Total angular displacement = _ avg t = 70 10 = 700 radians . The number of revolutions N is given by = N 2 . N = 2 = 700 2 = 350 . Answer: 350