COMEDK2023PhysicsRotational Motion
A thin circular ring of mass M and radius R rotates about an axis through its centre and perpendicular to its plane, with a constant angular velocity . Four small spheres each of mass m (negligible radius) are kept gently to the opposite ends of two mutually perpendicular diameters of the ring. The new angular velocity of the ring will be
Options
- A( M+4 m M )
- BM 4 m
- C( M M+4 m )
- D( M M-4 m )
Correct answer
C. ( M M+4 m )
Step-by-step solution
According to conservation of angular momentum, I = constant i.e. we can write, array rlrl I₁ ₁ & =I₂ ₂ & or & M R^2 =(M+4 m) R^2 ₂ & or & ₂ = ( M M+4 m ) & array