The masses of 200 ~g and 300 ~g are attached to the 20 ~cm and 70 ~cm marks of a light meter rod, respectively. The moment of inertia of the system about an axis passing through 50 ~cm mark is

Step-by-step solution

Given, 1 m₁=200 ~g =0.2 ~kg gathered m₂=300 ~g =0.3 ~kg l₁=50-20=30 ~cm l₁=0.3 ~m l₂=70-50=20 ~cm =0.8 ~m gathered Moment of inertia of the system about an axis passing through 50 ~cm mark (i.e. mid-point) aligned & 50 ~cm +50 ~cm &+20 ~cm + 14 +1-l₂ &l=m₁ l₁²+m₂ l₂² &=0.2 (0.3)²+0.3 (0.2)² &=0.036 ~kg ~m ² aligned