COMEDK2012PhysicsRotational Motion
A ring rolls down an inclined plane. The ratio of the rotational kinetic energy to translational kinetic energy is
Options
- A1: 3
- B1: 1
- C3: 1
- D2: 1
Correct answer
B. 1: 1
Step-by-step solution
The rotational kinetic energy of a ring is K_ R = 1 2 I ² For a ring, I =M R² and = v R K_ R = 1 2 (M R² ) ( v R )²= 1 2 M v² Also, translational kinetic energy, K_ T = 1 2 M v² K_ R =K_ T or K_ R : K_ T =1: 1