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IAT IISER2026ChemistryCoordination Compounds

Which one of the following octahedral complexes has the highest spin-only magnetic moment?

Options

  1. A[ Co ( NH ₃)₄ Cl ₂]
  2. B[ V ( H ₂ O )₄ I ₂]^+
  3. C[ Fe ( NH ₃)₄( CN )₂]^+
  4. D[ Cr ( H ₂ O )₄( OH )₂]

Correct answer

D. [ Cr ( H ₂ O )₄( OH )₂]

Step-by-step solution

The spin-only magnetic moment is given by the formula = n(n+2) BM, where n is the number of unpaired electrons. We determine the oxidation state, electronic configuration, and the number of unpaired electrons for each complex: For [ Cr ( H ₂ O )₄( OH )₂] : Let the oxidation state of Cr be x . x + 4(0) + 2(-1) = 0 x = +2 Cr ²⁺ has a 3d^4 configuration. Since H ₂ O and OH ^- are weak field ligands, the complex is high spin ( t_ 2g ^3 e_g^1 ). Number of unpaired electrons, n = 4 . = 4(4+2) = 24 4.90 BM. For [ V ( H ₂

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