JEE Advanced 2018Paper 2
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 2
- Subject
- Chemistry
- Chapter
- Ionic Equilibrium
JEE Advanced 2018 · Paper 2 · Chemistry · Ionic Equilibrium
The dilution processes of different aqueous solutions with water...
The dilution processes of different aqueous solutions with water are given in LIST-I. The effects of dilution of the solutions on are given in LIST-II.
(Note: The degree of dissociation \left(\alpha\right)< < 1;< < 1; [ {H}^{+} ]{H}^{+}10mLof0 . 1MNaOH + 20mLof0 .1 M60mL[ {H}^{+} ]20mLof0 . 1MNaOH + 20mLof0 . 1M80mL{\text{[H}}^{+} ]20mLof0 .1 MHCl + 20mLof0 .1 M80mL[ {H}^{+} ]10mLNi{\left(OH\right)}_{2}Ni{\left(OH\right)}_{2}20mLNi{\left(OH\right)}_{2}[ {H}^{+} ]\sqrt{}[ {H}^{+} ]\sqrt{2}$ times its initial value on dilution.
Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is


(Note: The degree of dissociation \left(\alpha\right)< < 1;< < 1; [ {H}^{+} ]{H}^{+}10mLof0 . 1MNaOH + 20mLof0 .1 M60mL[ {H}^{+} ]20mLof0 . 1MNaOH + 20mLof0 . 1M80mL{\text{[H}}^{+} ]20mLof0 .1 MHCl + 20mLof0 .1 M80mL[ {H}^{+} ]10mLNi{\left(OH\right)}_{2}Ni{\left(OH\right)}_{2}20mLNi{\left(OH\right)}_{2}[ {H}^{+} ]\sqrt{}[ {H}^{+} ]\sqrt{2}$ times its initial value on dilution.
Match each process given in LIST-I with one or more effect(s) in LIST-II. The correct option is
Options
- Aa-q;b-t;c-p;d-r;
- Ba-p;b-t;c-s;d-p;
- Ca-s;b-t;c-p;d-r;
- Da-s;b-q;c-p;d-t;
Correct answer
B. a-p;b-t;c-s;d-p;
Step-by-step solution
\left[{H}^{+}\right] will not change on dilution.
\left[{OH}^{-}\right]{\left[{H}^{+}\right]}_{1} = \sqrt{\dfrac{{k}_{w}{k}_{a}}{C}}\dfrac{{\left[{H}^{+}\right]}_{2}}{{\left[{H}^{+}\right]}_{1}} = \sqrt{\dfrac{{C}_{1}}{{C}_{2}}} = \sqrt{\dfrac{0 .05}{0 .025}}= \sqrt{2}( C )
Because of dilution, the solubility does not change. So, \left[{H}^{+}\right].