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JEE Advanced 2013Paper 1
Exam
JEE Advanced
Year
2013
Paper
Paper 1
Subject
Mathematics
Chapter
Application of Derivatives

JEE Advanced 2013 · Paper 1 · Mathematics · Application of Derivatives

The number of points in (- ∞ , ∞) , for which x ^ 2 - xsinx - x = 0...

The number of points in (−∞,∞)\left(- \infty , \infty\right), for which x2−xsinx−cos⁡x=0{x}^{2} - xsinx - \cos x = 0, is:The number of points in (- ∞ , ∞) , for which x ^ 2 - xsinx - x = 0 , is:

Options

  1. A66
  2. B44
  3. C22
  4. D00

Correct answer

C. 22

Step-by-step solution

f(x)=x2−xsinx−cos⁡xf\left(x\right) = {x}^{2} - xsinx - \cos x

f′(x)=2x−xcosx−sin⁡x+sin⁡x{f}^{'}\left(x\right) = 2x - xcosx - \sin x + \sin x

 =x(2−cos⁡x)= x\left(2 - \cos x\right)

We know that, \left(2 - \cos x\right)ispositiveforallrealnumbers,nowitdependsonis positive for all real numbers, now it depends onx. </p><p>So,. </p><p>So,f\left(x\right)is increasing if x>0x > 0

f(x)f\left(x\right) is decreasing if x<0x < 0

f(0)=−1f\left(0\right) = - 1

f(∞)=∞f\left(\infty\right) = \infty

f(−∞)=∞f\left(- \infty\right) = \infty

The number of points in (- ∞ , ∞) , for which x ^ 2 - xsinx - x = 0 , is:

So, it is clear that graph cuts the xx-axis at two points, so number of solutions are two.

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