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JEE Advanced2009MathematicsApplication of DerivativesActual

The maximum value of the function f(x)=2 x^3-15 x^2+36 x-48 on the set A= x x^2+20 9 x is

Correct answer

5

Step-by-step solution

Given, A= x x^2+20 9 x = x x [4,5] Now, f^ (x)=6 (x^2-5 x+6 ) Put f^ (x)=0 x=2,3f(2)=-20, f(3)=-21 , f(4)=-16, f(5)=7 From graph, maximum of f(x) on set A is f(5)=7 .

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