A tangent P T is drawn to the circle x²+y²=4 at the point P( 3 , 1) . A straight line L , perpendicular to P T is a tangent to the circle (x-3)²+y²-1 . Question: A possible equation of L is

Step-by-step solution

Equation of tangent P T to the circle x²+y²=4 at the point P( 3 , 1) is x 3 +y=4 Let the line L , perpendicular to tangent P T be x-y 3 + =0 As it is tangent to the circle (x-3)²+y²=1 Length of perpendicular from centre of circle to the Tangent = radius of circle. | 3+ 2 |=1 =-1 or -5 Equation of L can be x- 3 y=1 or x- 3 y=5