JEE Advanced 2012Paper 1
- Exam
- JEE Advanced
- Year
- 2012
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Circle
JEE Advanced 2012 · Paper 1 · Mathematics · Circle
The locus of the mid-point of the chord of contact of tangents...
The locus of the mid-point of the chord of contact of tangents drawn from points lying on the straight line to the circle is
Options
- A
- B
- C
- D
Correct answer
A.
Step-by-step solution
Any point on line can be considered as \left(\alpha, \frac{4 \alpha-20}{5}\right)A Bx^{2}+y^{2}=9\mathrm{P}\left(\alpha, \frac{4 \alpha-20}{5}\right)\alpha+\left(\frac{4 \alpha-20}{5}\right)=9...(i)A B(h, k)h x+k y=h^{2}+k^{2}....(ii)
\because \quad\therefore \quad \frac{h}{\alpha}=\frac{k}{\frac{4 \alpha-20}{5}}=\frac{h^{2}+k^{2}}{9}
\Rightarrow 5 k \alpha=4 h \alpha-20 h9 h=\alpha\left(h^{2}+k^{2}\right) and
Locus of is