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JEE Advanced 2009Paper 2
Exam
JEE Advanced
Year
2009
Paper
Paper 2
Subject
Mathematics
Chapter
Differentiation

JEE Advanced 2009 · Paper 2 · Mathematics · Differentiation

If the function f(x)=x^3+e^ (x)/(2) and g(x)=f^ -1 (x) , then the...

If the function f(x)=x3+ex2f(x)=x^3+e^{\frac{x}{2}} and g(x)=f−1(x)g(x)=f^{-1}(x), then the value of g′(1)g^{\prime}(1) is

Correct answer

0

Step-by-step solution

Given, g{f(x)}=xg\{f(x)\}=x ⇒g′{f(x)}f′(x)=1 If f(x)=1⇒x=0,f(0)=1\begin{array}{lc} \Rightarrow& g^{\prime}\{f(x)\} f^{\prime}(x)=1 \\ \text{ If }& f(x)=1 \Rightarrow x=0, f(0)=1 \end{array}Substitute x=0x=0 in Eq. (i), we get g′(1)=1f′(0)⇒g′(1)=2[\becausef′(x)=3x2+12ex/2⇒f′(0)=12]\begin{aligned}& g^{\prime}(1)=\frac{1}{f^{\prime}(0)}\\ & \Rightarrow \quad g^{\prime}(1)=2 \\ & {\left[\becausef^{\prime}(x)=3 x²+\frac{1}{2}e^{x / 2} \Rightarrow f^{\prime}(0)=\frac{1}{2}\right]} \\ & \end{aligned}
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