JEE Main 20244 AprilMorning Shift
- Exam
- JEE Main
- Year
- 2024
- Date
- 4 April
- Shift
- Morning Shift
- Subject
- Mathematics
- Chapter
- Differentiation
JEE Main 2024 · 4 April · Morning Shift · Mathematics · Differentiation
Let f(x)=x^5+2 e^ x / 4 for all x ∈ R . Consider a function g(x)...
Let
f(x)=x5+2ex/4 for all
x∈R. Consider a function
g(x) such that
(g∘f)(x)=x for all
x∈R. Then the value of
8g′(2) is :
Step-by-step solution
f(x)=2 when x=0∵g′(f(x))f′(x)=1g′(2)=f′(0)1∵f′(x)=5x4+42ex/4g′(2)=2 Ans =16 Option (1)
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