JEE Advanced 2025Paper 1
- Exam
- JEE Advanced
- Year
- 2025
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Functions
JEE Advanced 2025 · Paper 1 · Mathematics · Functions
Let ℕ denote the set of all natural numbers, and ℤ denote the set...
Let denote the set of all natural numbers, and denote the set of all integers. Consider the functions and defined by
\begin{cases}(n+1) / 2 & \text{ if } n \text{ is odd } \\ (4-n) / 2 & \text{ if } n \text{ is even }\end{cases}And
$g(n)=\left\{\begin{array}{cc}3+2 n & \text{\text{ if } } n \geq 0 \\ -2 n & \text{\text{ if } } n <0\end{array}$\right.
Define for all , and for all .
Then which of the following statements is (are) TRUE?
Options
- A is NOT one-one and is NOT onto
- B is NOT one-one but is onto
- C is one-one and is onto
- D is NOT one-one but is onto
Correct answer
A. is NOT one-one and is NOT onto
Step-by-step solution
\therefore \mathrm{f}(\mathrm{n})( is one-one and into function
(())=2+, \in
fog is one-one and into
\begin{cases}4+n & \text{ if } n \text{ is odd natural number } \\ 7-n & \text{ if } n=2,4 \\ n-4 & \text{ if } n \text{ is even natural number and } n \geq 6\end{cases} gof is many one and into