Considering only the principal values of the inverse trigonometric functions, the value of 3 2 cos - 1 2 2 + π 2 + 1 4 sin - 1 2 2 π 2 + π 2 + tan - 1 2 π is _______. (If the numerical value has more than two decimal places, truncate/round-off the value to TWO decimal places)

Step-by-step solution

3 2 cos - 1 2 2 + π 2 + 1 4 sin - 1 2 2 π 2 + π 2 + tan - 1 2 π = 3 2 tan - 1 π 2 + 1 4 tan - 1 2 2 π π 2 - 2 + tan - 1 2 π = π 2 + 1 2 tan - 1 π 2 - 1 4 tan - 1 2 2 π 2 - π 2 = π 2 + 1 2 tan - 1 π 2 - 1 4 tan - 1 2 · π 2 1 - π 2 2 = π 2 + 1 2 tan - 1 π 2 - 1 4 - π + 2 tan - 1 π 2 = π 2 + π 4 = 3 π 4 = 2 . 36