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JEE Advanced 2014Paper 2
Exam
JEE Advanced
Year
2014
Paper
Paper 2
Subject
Mathematics
Chapter
Probability

JEE Advanced 2014 · Paper 2 · Mathematics · Probability

Paragraph: Box 1 contains three cards bearing numbers 1,2,3 ; box 2...

Paragraph: Box 11 contains three cards bearing numbers 1,2,31,2,3; box 22 contains five cards bearing numbers 1,2,3,4,51,2,3,4,5; and box 33 contains seven cards bearing numbers 1,2,3,4,5,6,71,2,3,4,5,6,7. A card is drawn from each of the boxes. Let xix_{i} be the number on the card drawn from the ithi^{t h} box, i=1,2,3i=1,2,3.
Question: The probability that x1+x2+x3x_{1}+x_{2}+x_{3} is odd, is

Options

  1. A29105\dfrac{29}{105}
  2. B53105\dfrac{53}{105}
  3. C57105\dfrac{57}{105}
  4. D12\dfrac{1}{2}

Correct answer

B. 53105\dfrac{53}{105}

Step-by-step solution

Case I: One odd, 2 even
Total number of ways =2×2×3+1×3×3+1×2×4=29= 2 \times 2 \times 3 + 1 \times 3 \times 3 + 1 \times 2 \times 4 = 29
Case II: All 3 odd
Number of ways =2×3×4=24= 2 \times 3 \times 4 = 24
Favourable ways = 53
Required probability =533×5×7=53105= \dfrac{53}{3 \times 5 \times 7} = \dfrac{53}{105}
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