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JEE Advanced 2020Paper 1
Exam
JEE Advanced
Year
2020
Paper
Paper 1
Subject
Mathematics
Chapter
Quadratic Equation

JEE Advanced 2020 · Paper 1 · Mathematics · Quadratic Equation

Suppose a, b denote the distinct real roots of the quadratic...

Suppose a,ba, b denote the distinct real roots of the quadratic polynomial x2+20x−2020{x}^{2} + 20x - 2020 and suppose c,dc, d denote the distinct complex roots of the quadratic polynomial x2−20x+2020{x}^{2} - 20x + 2020. Then the value of ac\left(a - c\right) + ad\left(a - d\right) + bc\left(b - c\right) + bd\left(b - d\right)

Options

  1. A00
  2. B80008000
  3. C80808080
  4. D1600016000

Correct answer

D. 1600016000

Step-by-step solution

Finding the sum and product of roots of the two given quadratic equations i.e.

a+b=−20 and ab=−2020...........(i)a + b = - 20 \text{ and } ab = - 2020 . . . . . . . . . . . \left(i\right)

c+d=20 and cd=2020...........(ii)c + d = 20 \text{ and } cd = 2020 . . . . . . . . . . . \left(ii\right)

Now, ac(a−c)+ad(a−d)+bc(b−c)+bd(b−d)ac\left(a - c\right) + ad\left(a - d\right) + bc\left(b - c\right) + bd\left(b - d\right)

=a2(c+d)−a(c2+d2)+b2(c+d)−b(c2+d2)= {a}^{2}\left(c + d\right) - a\left({c}^{2} + {d}^{2}\right) + {b}^{2}\left(c + d\right) - b\left({c}^{2} + {d}^{2}\right)

=(a2+b2)(c+d)−(a+b)(c2+d2)= \left({a}^{2} + {b}^{2}\right)\left(c + d\right) - \left(a + b\right)\left({c}^{2} + {d}^{2}\right)

={(a+b)2−2ab}(c+d)−(a+b)= \left\{{\left(a + b\right)}^{2} - 2ab\right\}\left(c + d\right) - \left(a + b\right)\left\{{\left(c + d\right)}^{2} - 2cd\right\}</p><p></p><p>= \left\{{\left(- 20\right)}^{2} - 2\left(- 2020\right)\right\}\left(20\right) - \left(- 20\right)\left\{{\left(20\right)}^{2} - 2\left(2020\right)\right\}(usingequations(i) and (ii)(using equations \left(i\right) \text{ and } \left(ii\right))

=16000= 16000

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