JEE Advanced 2012Paper 1
- Exam
- JEE Advanced
- Year
- 2012
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Quadratic Equation
JEE Advanced 2012 · Paper 1 · Mathematics · Quadratic Equation
The value of 6+ _ (3)/(2) ( 1 3 2 4- 1 3 2 4- 1 3 2 4- 1 3 2 ) is
The value of
Correct answer
0
Step-by-step solution
Let \begin{aligned}
\therefore \quad & 6+\log _{\frac{3}{2}}\left(\frac{4}{9}\right)=6+\log _{\frac{3}{2}}\left(\frac{3}{2}\right)^{-2} \\
&=6-2=4
\end{aligned}$$