JEE Advanced2012MathematicsQuadratic EquationActual

The value of 6+ _ 3 2 ( 1 3 2 4- 1 3 2 4- 1 3 2 4- 1 3 2 ) is

Correct answer

Step-by-step solution

Let x= 1 3 2 4- 1 3 2 4- 1 3 2 4- 1 3 2 x= 1 3 2 4-x 3 2 x= 4-x array l 18 x²=4-x 18 x²+x-4=0 (9 x-4)(2 x+1)=0 x= 4 9 or x=- 1 2 array (Not possible because log is not define for -ve value) aligned & 6+ _ 3 2 ( 4 9 )=6+ _ 3 2 ( 3 2 )⁻² &=6-2=4 aligned

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